C3(2)+C4(2)+------Cn+2(2)=[3*2+4*3+------(n+2)(n+1)]/2=[2^2+3^2+-----+(n+1)^2+2+3+------+(n+1)]/2=[(n+1)(n+2)(2n+3)-6]/12+n(n+3)/4=(5n^3+9n^2+22n)/12