一道初一数学题,(乘法公式)数学高手快进来看一看啦!!!

2024-12-26 14:30:15
推荐回答(2个)
回答1:

3²-1²=4*2=4*[(3+1)/2]
4²-2²=4*3=4*[(4+2)/2]
5²-3²=4*4=4*[(5+3)/2]

所以(n+2)²-n²=4*[(n+2+n)/2]=4*(n+1)

(n+2)²-n²
=(n+2+n)(n+2-n)
=(2n+2)*2
=4(n+1)
正确

回答2:

(n+2)²-n²
=(n+2+n)(n+2-n)
=(n+2)²-n ²
=4(n+1)
=4n+4