应该是AB=BC，DB=BE∠ABD+∠DBC=90∠DBC+∠CBE=90，∠ABD=∠CBE△ABD≌△CBEAD=CE2、相等∠ABC=∠DBE=90，∠ABC+∠CBD=∠DBE+∠CBD，∠ABD=∠CBE△ABD≌△CBEAD=CE
