48个桃子,放在13个篮子,且每个篮子只能放奇数,怎么放?

2025-03-15 03:03:16
推荐回答(4个)
回答1:

回答2:

奇数个篮子,每个放奇数个,奇数个奇数相加等于奇数,不可能等于48这个偶数。

是不可能的,是奇数: 3个篮子。除非把一个不放,只能是奇数,任何奇数个奇数相加,而48个桃是偶数,放奇数个桃子,每个篮子里只能放奇数个桃子,不可能为偶数。

扩展资料:

关于偶数和奇数,有下面的性质:

(1)两个连续整数中必是一个奇数一个偶数;

(2)奇数与奇数的和或差是偶数;偶数与奇数的和或差是奇数;任意多个偶数的和都是偶数;单数个奇数的和是奇数;双数个奇数的和是偶数;

(3)两个奇(偶)数的和或差是偶数;一个偶数与一个奇数的和或差一定是奇数;

(4)除2外所有的正偶数均为合数;

(5)相邻偶数最大公约数为2,最小公倍数为它们乘积的一半;

(6)奇数与奇数的积是奇数;偶数与偶数的积是偶数;奇数与偶数的积是偶数;

(7) 偶数的个位一定是0、2、4、6或8;奇数的个位一定是1、3、5、7或9;

(8)任何一个奇数都不等于任何一个偶数;若干个整数的连乘积,如果其中有一个偶数,乘积必然是偶数。

回答3:

是不可能的,zhidao是奇数:
3个篮子。除非把一个不放,只能是奇数,任何奇数个奇数相加,而48个桃内是偶数,放奇数个桃子,每个篮子里只能放奇数个桃子,不可能为偶数。篮子13。这题给你容换一下,有无办法让篮子里桃子之和为偶数

回答4:

按道理是不行的,13个奇数相加不可能等于偶数48,那么有俩篮子叠着放,上面放一个,其他随意安排

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