推荐回答(6个)
1、(还原问题)300÷(1-1/5)÷(1-1/5)【第二天修了余下的1/5,还剩下300米没有修,说明这300米是剩下的4/5,所以用300÷(1-1/5),求出第一天修筑以后的米数,同理,300÷(1-1/5)是全长的4/5,所以300÷(1-1/5)÷(1-1/5)】
2、(分数应用题)25÷(1/2-2/5)【中点是全长的1/2,全长的1/2-全长的2/5,是中点与以行路的差占全长的几分之几,这差是25,所以 25÷(1/2-2/5)】
3、(百分数应用题)48÷(1-20%)【现价比原价降低了20%,说明现价是原价的1-20%,现价是48元,所以48÷(1-20%)求出原价。】
4、(分数应用题)102* 18+16分之18【从甲班调出全班人数的1/18到乙班,则两班人数同样多,说明两班人数原来的比是18:16(甲班比乙班)按比例分配,所以102* 18+16分之18】
1、(分数应用题)解:设原有x人。
3/8x+27=6/7x
6/7x-3/8x=27
x=56
2、(分数应用题)(24+12)÷(1-2/5-1/3)=135( kg)
135*2/5+135*1/3-12=99(kg)
3、 56* 4+3分之4=32(人)
56* 4+3分之3=24(人)
32÷8/15=60(人)
60-24=36(人)
4、486÷3÷(24-2*3)+2*3=15(cm)
5、解:设总量为x。4\7x+(4\7x除以2减去12)=x乘以27\27+8
1.30/(1-1/5-4/5*1/5)
2.25/(1/2-2/5)
3.48/(1-20/100)*20/100
4.9/(9+8)*102
1.解:设原有X人。
X-5/8*X+27=6/7*X
2.(24-12)/(1-2/5-1/3)
3.(56*4/7)/(8/15)-56
4.486/(24-3*2)/3
5.解:设共有X千克。
4/7*X*(1+2)+12=27/(27+8)*X
1、300÷(1-1/5)÷(1-1/5)=468.75
2、25÷(1/2-2/5)=250
3、48÷(1-20%) =60
4、102* 18+18/16=1837.125
1、解:设原有x人。
3/8x+27=6/7x
6/7x-3/8x=27
x=56
2、(24+12)÷(1-2/5-1/3)=135( kg)
135*2/5+135*1/3-12=99(kg)
3、 56* 4+3分之4=32(人)
56* 4+3分之3=24(人)
32÷8/15=60(人)
60-24=36(人)
4、486÷3÷(24-2*3)+2*3=15(cm)
5、解:设总量为x。4\7x+(4\7x除以2减去12)=x乘以27\27+8 x=15.45
第一题:1-1/5=4/5 1/5*4/5=4/25 300÷4/25=...
第二题:1÷2=1/2 1/2-2/5=1/10 25÷1/10=...
第三题:48÷(1-20%)=60(元) 60*20%=...
第四题:1/18*2=9/1 102÷(1+1+1/9)=(等等,你这个数是不是出错了?)
第一题: 1-6/7=1/7 5/8-1/7=27/56 27÷27/56=56(人)
第二题: 24-12=12(千克) 2/5+1/3=11/15 1-11/15=4/15 12÷4/15=45(千克) 45*11/15=33(千克)
第三题: 解:设转进来X名男生。 56(4/7)=(56+X)(8/15) 解得:X=4
第四题: 2*3=6(厘米) 24-6=18(厘米) 486÷3÷18=9(厘米) 9+6=15(厘米)
第五题: 解:设这批农药共X千克。 (X*4/7)+(X*2/7-12/2)=27/(27+8)
解得:X=7.9
(妈妈呀,累死我了!!!)
1.300除以(1\5+1\5)
2.520除以2\5
3.480乘以20%
4.102除以2加上1\18乘以102
1.1-5/8=3/8 27÷(6/7-3/8)
2.(24+12)÷(1-2/5-1/3)
3.原来女生与男生的比是4比3现在的比是8比7因为女生人数没变,所以原来的比可以化成8比6.56乘以(7加8)乘以8
4.486除以24除以3
5.解:设总量为x。4\7x+(4\7x除以2减去12)=x乘以27\27+8
1.300÷(1-1/5)÷(1-1/5)
2.25÷(1/2-2/5)
3.48÷(1-20%)
4.(102÷2)÷(1+1/18)
1.1-5/8=3/8 27÷(6/7-3/8)=56(人)
2.(24+12)÷(1-2/5-1/3)
3.56*4/7=(56+X)*8/15
4.486/3/(24-2*3)+2*3
5.(X*4/7)+(X*2/7-12/2)=27/(27+8)
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