已知sinx+siny=1⼀3,求 siny-cos²x的最大值?

2024-12-31 14:40:48
推荐回答(2个)
回答1:

sinx+siny=1/3
siny=1/3-sinx
因为-1<=siny<=1
所以-1<=1/3-sinx<=1
-2/3<=sinx<=3/4
又-1<=sinx<=1
所以-2/3<=sinx<=1

siny-(cosx)^2
=1/3-sinx-[1-(sinx)^2]
=(sinx)^2-sinx-2/3
=(sinx-1/2)^2-11/12
对称轴sinx=1/2
因为-2/3<=sinx<=1
所以sinx=-2/3时 siny-(cosx)^2最大值4/9

回答2:

4/9