用分部积分法
∫xsin^2xdx=0.5∫x(1-cos2x)dx
=0.5∫xdx-0.25∫xdsin2x
=0.25x^2-0.25xsin2x+0.25∫sin2xdx
=0.25x^2-0.25xsin2x-0.125cos2x+C
=∫x[(1-cos2x)/2]dx
=1/4(x^2-∫xdsin2x)
=1/4(x^2-xsin2x+∫sin2xdx)
=x^2/4-(xsin2x)/4-(cos2x)/8+C
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