e的x次方乘以x的平方的积分

2024-12-23 15:32:52
推荐回答(3个)
回答1:

∫x^2*e^(x^2)dx和∫x^2*e^(-x^2)dx,不定积分均无法用初等函数表示,但∫x^2*e^(-x^2)dx在[0,+∞)上的定积分可求出

∫(0→+∞)x^2*e^(-x^2)dx
=∫(0→+∞)(-1/2)x*e^(x^2)d(-x^2)
=(-1/2)∫(0→+∞)x*d[e^(-x^2)]
=(-1/2){[x*e^(-x^2)]|(0→+∞) - ∫(0→+∞)e^(-x^2)dx}
=(1/2)∫(0→+∞)e^(-x^2)dx
=√π/4=(1/4)√π

回答2:

f(x) = e^x * x^2

F(x) = x^2*e^x - 2(e^x*x+e^x)+C

回答3:

∫xe^(x^2) dx
=(1/2)∫ e^(x^2) dx^2
=(1/2) e^(x^2) + C