这几道题,求帮忙!学霸们帮下!急用!

2024-12-27 08:46:26
推荐回答(2个)
回答1:

回答2:

1.3/(x-4)-24/(x^2-16)
   ={3(x+4)-24}/(x-4)(x+4)
   =(3x-12)/(x-4)(x+4)
   =3(x-4)/(x-4)(x+4)
   =3/(x+4)

8.(x-4)/(x+2)x(x-2)

9.(2x-5)/(x2-5x+6)=1/(x-2)+1/(x-3)

∴原式=1/(x-2)

10.原式=2(2a-3)/(2a+3)(2a-3) - 3(2a+3)/(2a-3)(2a+3) +15/(2a+3)(2a-3)

            =(4a-6-6a-9+15)/(2a+3)(2a-3)

            =-2a/(2a+3)(2a-3)

7.解:12/m2-9+2/3-m+2/m+3

        =12/(m+3)(m-3)-2(m+3)/(m+3)(m-3)+2(m-3)/(m+3)(m-3)=12-2(m+3)+2(m-3)/(m+3)(m-3)

=0;

4.(1/x-3)+(1-x/6+2x)-(6/x^2-9)
=[2(x+3)+(1-x)(x-3)-6*2]/2*(x^2-9)
=(2x+6-x^2+4x-3-12)/2*(x^2-9)
=(-x^2+6x-9)/2*(x^2-9)
=-(x-3)^2/2*(x+3)(x-3)
=-(x-3)/2*(x+3)
=(3-x)/(2x+6)

 


 

 

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