七年级(-4)×(-5)×0.25的乘法交换律怎么写

2024-12-30 05:51:02
推荐回答(4个)
回答1:

原式=(-4)×0.25×(-5)
=-1×(-5)
=5
乘法交换律:a×b=b×a,本题中为a×b×c=a×c×b
希望对你有帮助,望采纳。

回答2:

(-4)×(-5)×0.25
=(-4)×0.25x(-5)
=(-1)x(-5)
=5

回答3:

=4×5×0.25
=4×0.25×5
=1×5
=5

回答4:

-4×0.25×(-5)
=-1×(-5)
=5

求采纳