(1+2)(1+2눀)(1+2대)…(1+2대눀)=?

(1+2)(1+2눀)(1+2대)…(1+2대눀)=?
2024-12-28 11:59:26
推荐回答(1个)
回答1:

首先:
(1+2)(1+2^2)(1+2^4)(1+2^8)(1+2^16)(1+2^32)
=(2-1)(2+1)(2^2+1)(2^4+1)((2^8+1)(2^16+1)(2^32+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
····
=(2^64-1)