2x^2-7x+6=0解:(2x-3)(x-2)=0 2x-3=0 x-2=0 x=3/2 或者 x=2
解:2x²-7x+6=0十字相乘 (x-2)(2x-3)=0 x-2=0或2x-3=0 ∴x=2或3/2
2x^2-7x+6=0x^2-7x/2=-3(x-7/4)^2=1/16x-7/4=±1/4x1=2 x2=-3/2