化简:sin(2π-α)cos(π⼀2+α)+sin(3π⼀2-α)cos(π-α)=

2024-12-21 12:15:34
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回答1:

解:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)
=(-sinα)*(-sinα)+(-cosα)*(-cosα)
=(sinα)^2+(cosα)^2=1