∵2x²-2x-3=0,∴2x²-1=2x+2=2(x+1)∴(x-1)²/(x²-1)+ (2x²-x)/(x+1)=(x-1)²/[(x-1)(x+1)]+(2x²-x)/(x+1)=（x-1)/(x+1)+(2x²-x)/(x+1)=(2x²-1)/(x+1)=2(x+1)/(x+1)=2
