3*[1*2+2*3+3*4+··+n(n+1)]=3*{1/3*(1*2*3-0*1*2)+1/3*(2*3*4-1*2*3)+1/3*(3*4*5-2*3*4)+........+1/3*[n*(n+1)(n+2)-(n-1)*n*(n+1)]}=3*1/3*{1*2*3-0*1*2+2*3*4-1*2*3+3*4*5-2*3*4+........+n*(n+1)(n+2)-(n-1)*n*(n+1)}=3*1/3*{n*(n+1)(n+2)-0*1*2}=n*(n+1)(n+2)