6a的2次方减5a(-a加2b-1)加4a(-3a-2分之5b-4分之3等于多少

2024-12-24 14:03:37
推荐回答(2个)
回答1:

6a的2次方减5a(-a加2b-1)加4a(-3a-2分之5b-4分之3)
=6a²+5a²-10ab+5a-12a²-10ab-3a
=a²-20ab+2a

回答2:

6a^2-5a*(-a+2b-1)+4a*(-3a-5b/2-3/4)
=12a^2+5a^2-10ab+5a-12a^2-10ab-3a
=5a^2-20ab+2a