设p=(2/a)+3b�0�5，q=(2/b)+3a�0�5∴p+q=2(a+b)/ab+3(a+b)�0�5-6abp-q=2(a-b)/ab-3(a+b)(a-b)韦达定理得a+b=7，ab=8 ∴(a-b)�0�5=(a+b)�0�5-4ab=17∴a>b，则a-b=√17，带入后得p+q=403/4，p-q=(-83√17)/4∴p=(403-83√17)/8
