x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)
(x-2+2)/(x-2)+(x-7-2)/(x-7)=(x-1+2)/(x-1)+(x-6-2)/(x-6)
1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)
1/(x-2)+1-1/(x-7)=1/(x-1)-1/(x-6)
[x-7-(x-2)]/[(x-1)(x-2)]=[x-6-(x-1)][(x-6)(x-7)]
-5/[(x-1)(x-2)]=-5[(x-6)(x-7)]
(x-1)(x-2)=(x-6)(x-7)
x^2-3x+2=x^2-13x+42
10x=40
x=4
经验证，x=4不是增根
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