(1)已知lg2=a,lg3=b,试用a,b表示 log215;(2)求值:(279)12+(lg5)0+(2764)?13

2024-12-18 16:55:13
推荐回答(1个)
回答1:

(1)log215=

lg3+lg5
lg2
=
lg3+1?lg2
lg2
=
b+1?a
a

(2)原式=[(
5
3
)2]
1
2
+1+[(
4
3
)?3]?
1
3
=
5
3
+1+
4
3
=4.