已知x=√3+√2⼀√3-√2,Y=√3-√2⼀√3+√2,求代数式3x05-5xy+3y05的值

2024-12-24 12:18:21
推荐回答(1个)
回答1:

x=√3+√2/√3-√2
=(√3+√2)^2/(√3-√2)(√3+√2)
=5+2√6
y=(√3-√2)/(√3+√2)
=(√3-√2)^2/(√3+√2)(√3-√2)
=5-2√6
3x�0�5-5xy+3y�0�5
=3(x-y)^2+xy
=3(5+2√6-5+2√6)^2+(5+2√6)(5-2√6)
=3*96+1
=289