dx/dy = (y²-x)/y = y - x/y对dx/dy = - x/y,解得x = C/y用常数变易法设x = C(y)/ydx/dy = C'(y)/y - C(y)/y²y - x/y = y - C(y)/y²则C'(y)/y - C(y)/y² = y - C(y)/y²C'(y) = y²C(y) = y³/3 + C通解为y³ - 3xy = C