求微分方程dy⼀dx=y⼀(y^2-x)的通解

2025-01-05 09:29:26
推荐回答(1个)
回答1:

dx/dy = (y²-x)/y = y - x/y
对dx/dy = - x/y,解得x = C/y
用常数变易法
设x = C(y)/y
dx/dy = C'(y)/y - C(y)/y²
y - x/y = y - C(y)/y²

则C'(y)/y - C(y)/y² = y - C(y)/y²
C'(y) = y²
C(y) = y³/3 + C

通解为y³ - 3xy = C