(1)√18 =3√2
(2)3√3-√75 =3√3-5√3=-2√3
(3)(√20+√5)/√5-√2
=(√20+√5)(√5+√2 )/【(√5-√2 )(√5+√2)】
=(10+5+√40+√10)/3
=(15+3√10)/3
= 5+√10
(4)√(49×121)=77
(1)√18 =3√2
(2)3√3-√75 =3√3-5√3=-2√3
(3)(√20+√5)/√5-√2
=√4+1-√2
=3-√2
(4)√(49×121)
=√49×√121
=7×11
=77。