函数f(x)的定义域为R令g(x)=-x�0�5+2x+3g(x)=-(x-1)�0�5+4≤4∴原函数f(x)=3^(-x�0�5+2x+3)的单调递增区间为(-∞,1]单调递减区间为[1,+∞)值域为(0,3^4]即(0,81]
