负的(2的3次方)加(负2的3次方)减去(负6又2分之1乘以13分之4除以负4除2的绝对值)的答案是多少?

2024-12-20 02:34:44
推荐回答(2个)
回答1:

- 2 ³ + (- 2)³ - (- 6 又 1 / 2 × 丨4 / 13 ÷ (- 4 ÷ 2) 丨)
= - 8 - 8 + 13 / 2 × 丨4 / 13 ÷ (- 2)丨
= - 16 + 13 / 2 × 丨- 2 / 13 丨
= - 16 + 13 / 2 × 2 / 13
= - 16 + 1
= - 15

回答2:

-(2³)+(-2)³-│(-6-1/2)×4/13÷(-4)/2│
=-8-8-│-13/2×4/13×(-1/2)│
=-16-1/4
=-65/4