(6x-1)(2x-1)(3x-1)(x-1)+x05 因式分解

2024-12-29 21:01:37
推荐回答(2个)
回答1:

(6x-1)(2x-1)(3x-1)(x-1)+x^2=(6x^2-7x+1)(6x^2-5x+1)+x^2=[(6x^2+1)-7x][(6x^2+1)-5x]+x^2=(6x^2+1)^2-12x(6x^2+1)+36x^2=(6x^2+1-6x)^2

回答2:

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