答：原式=(x²+2x+1)/(x+2)+(x²-1)/(x-1)-x/(x+2)=(x²+2x+1-x)/(x+2)+(x-1)(x+1)/(x-1)=(x²+x+1)/(x+2)+x+1=(x²+x+1+x²+3x+2)/(x+2)=(2x²+4x+3)/(x+2)=2x+3/(x+2)=2*(√3-2)+3/(√3-2+2)=2√3-4+√3=3√3-4
