已知函数f(x)=2√3sinxcosx 2cos눀x-1(x∈R)

2024-12-24 18:24:13
推荐回答(1个)
回答1:

f(x)=2√3sinxcosx +2cos²x-1
=√3sin2x+ 1+ cos2x-1
==√3sin2x+cos2x
=2sin(2x+π/6)

最小正周期=π
x【0,π/2】 2x+π/6【π/6,7π/6】
最大值为2 最小值为0
2kπ+π/2<2x+π/6<2kπ+3π/2
kπ+π/6