{x=sinacosa+cos²a ①
{y=sinacosa+sin²a ②
...................................
①+②得:
(x+y)=1+sin2a ③
①-②得:
(x-y)=cos2a ④
1=sin²2a+cos²2a=[(x+y)-1]²+(x-y)²
x²+y²-x-y=0
(x-1/2)²+(y-1/2)²=(√2/2)²
轨迹是一个圆
两式相除: y/x=tana
x=cosa(sina+cosa)=(cosasina+(cosa)^2)/((cosa)^2+(sina)^2)
=(tana+1)/(1+(tana)^2)=(y/x+1)/(1+(y/x)^2)
即 x=(y/x+1)/(1+(y/x)^2)
化简:x^2+y^2-x-y=0
希望对你有点帮助!
答:
x=cosa(sina+cosa)=(1/2)sin2a+(cos2a+1)/2=(√2/2)sin(2a+π/4)+1/2
y=sina(sina+cosa)=(1-cos2a)/2+(1/2)sin2a=-(√2/2)cos(2a+π/4)+1/2
所以:
(2x-1)²+(2y-1)²=2
x^2+y^2=(sina+cosa)^2=sina^2+cosa^2+2sinacosa=sina^2+sinacosa+cosa^2+sinacosa=sina(sina+cosa)+cosa(sina+cosa)=x+y