用洛必达法则求limx→0 x^mlnx(m>0)的极限?

2024-12-15 02:24:02
推荐回答(1个)
回答1:

   lim(x→0)(x^m)lnx
  = lim(x→0)lnx/x^(-m) (∞/∞)
  = lim(x→0)(1/x)/[(-m)x^(-m-1)]
  = lim(x→0)(x^m)/(-m)
  = 0