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1⼀i^2 从i=1到n的求和公式

2025-04-07 22:38:01

推荐回答（3个）

回答1：

还没有公式，只有∑(1~∞)1/i²=π²/6
http://zh.wikipedia.org/wiki/%E9%BB%8E%E6%9B%BC%CE%B6%E5%87%BD%E6%95%B8

回答2：

还木有公式不过貌似答案是1 ∑(1~∞)1/i² 此为收敛函数收敛于1

回答3：

用等比数列的求和公式

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