1、判断为电流并联负反馈。2、反馈系数F=-If/Io=-R2/(R2+RF)Io/Io=-R2/(R2+RF)3、Ai=Io/Ii=1/F=-(R2+RF/R2)4、ui=IiR1，uo=IoRLuo/ui=IoRL/IiR1=-(RL/R1)Ai=-(RL/R1)(R2+RF/R2)
