多项式 2xy-x^2-y^2+1 因式分解

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2025-01-02 06:50:12
推荐回答(4个)
回答1:

2xy-x^2-y^2+1 =-(x^2-2xy+y^2-1)=-[(x-y)^2-1]=-(x-y+1)(x-y-1)=(y-x-1)(x-y-1)

回答2:

=-(-2xy+x^2+y^2-1 )
=-((x-y)^2-1)
=-(x-y+1)(x-y-1)

回答3:

[1+(x-y)][1-(x-y)]

回答4:

2xy-x²-y²+1
=-(x²-2xy+y²-1)
=-[(x-y)²-1]
=-(x-y+1)(x-y-1)