谁会这道初三数学题(最好写清过程,谢谢):按指定的方法解下列方程:①2⼀1(2x-1)눀-32=0(

2024-12-22 17:03:21
推荐回答(2个)
回答1:

①1/2(2x-1)²-32=0
(2x-1)²=64
2x-1=土8
2x-1=8或2x-1=-8
∴X1=9/2, X2=-7/2

②3x²+4x+1=0
x²+4/3x=-1/3
x²+4/3x+4/9=-1/3+4/9
(X+2/3)²=1/9
X+2/3=1/3或X+2/3=-1/3
∴X1=-1/3, X2=-1

③x²-x-1=0(公式法);
△=1+4=5
X1=(1+√5)/2,X2=(1-√5)/2

④x²-1=3x-3
(x-1)(x+1)-3(x-1)=0
(x-1)(x-2)=0
X1=1, X2=2

回答2:

①1/2(2x-1)²-32=0
(2x-1)²=64
2x-1=土8
2x-1=8或2x-1=-8
∴X1=9/2, X2=-7/2