设Z=e^u-2v,而u=sinx,v=x^3,求dz⼀dx,求大神解答

2024-12-23 04:06:37
推荐回答(2个)
回答1:

解:
dz/dx=偏z/偏u×偏u/偏x+偏z/偏v×偏v/偏x
=(e^u)(cosx)+(-2)(3x^2)
=cosx(e^(sinx))-6x^2

回答2:

du/dx=cosx dv/dx=3x^2
dz/dx=e^u*du/dx-2dv/dx
=e^u*cosx-6x^2