用加减法解下列方程7+x-3y⼀4=2x-y+5⼀3 10(x-y)-4(1-x)⼀3=y ?

2024-12-26 02:15:26
推荐回答(1个)
回答1:

7+x-3y/4=2x-y+5/3
同时乘以12化为整数:84+12x-9y=24x-12y+20
12x-3y=64;(a)
10(x-y)-4(1-x)/3=y
同时乘以3化为整数:30(x-y)-4(1-x)=3y
30x-30y-4+4x-3y=0
34x-33y=4;(b)
a式*11-b式:132x-33y-(34x-33y)=704-4
98x=700
x=0.14,y=-20.773~