2x눀-3x=2 2x눀-4根号下2x+3=0 3x눀+2x=0 用配方法解方程

急啊
2024-12-19 05:45:17
推荐回答(2个)
回答1:

2x²-3x=2
2x²-3x-2=0
2(x^2-3/2x+9/16)=25/8
(x-3/4)^2=25/16
x-3/4=+-5/4
x1=2 x2=-1/2

2x²-4根号下2x+3=0
2(x^2-2根号下2x+2)=1
(x-根号下2)^2=1/2
x-根号下2=+-根号下2/2
x1=3根号下2/2
x2=根号下2/2
3x²+2x=0
3(x^2+2/3x+1/9)=1/3
(x+1/3)^2=1/9
x+1/3=+-1/3
x1=-2/3
x2=0

回答2:

2x²-3x=2
2x²-3x-2 =0
(√2x)²-2*√2x*3/(2*√2)+[3/(2*√2)]^2-25/8=0
(√2x-3/(2*√2))²-25/8=0
(√2x-3/(2*√2))²=25/8
√2x-3/(2*√2)=5/(2*√2)或√2x-3/(2*√2)=-5/(2*√2)
√2x-3/(2*√2)=5/(2*√2)
√2x=8/(2*√2)
x=2
x=-1/2