待定系数法
设通项公式 是
a *(n-2)(n-3)(n-4)(n-5)(n-6) + b *(n-1)(n-3)(n-4)(n-5)(n-6) + c *(n-1)(n-2)(n-4)(n-5)(n-6) +
d *(n-1)(n-2)(n-3)(n-5)(n-6) + e *(n-1)(n-2)(n-3)(n-4)(n-6) + f *(n-1)(n-2)(n-3)(n-4)(n-5)
有
a *(1-2)(1-3)(1-4)(1-5)(1-6) = 1
b *(2-1)(2-3)(2-4)(2-5)(2-6) =0
c *(3-1)(3-2)(3-4)(3-5)(3-6) =1/3
d *(4-1)(4-2)(4-3)(4-5)(4-6) =0
e *(5-1)(5-2)(5-3)(5-4)(5-6) =1/5
f *(6-1)(6-2)(6-3)(6-4)(6-5) = 0
算出abcdef代入待定的通项公式即可
n为奇数,a=1/n n为偶数,a=0 不明白可以追问!