﹙1﹚
原式=1-[x-1/﹙1-x﹚]²·﹙x-1﹚²/﹙x²-x+1﹚
=1-﹙x²+x-1﹚
=﹣x²+x
当x=﹣1/3时
﹣x²+x
=﹣﹙﹣1/3﹚²+﹣1/3
=﹣1/9+1/3
=﹣4/9
﹙2﹚
原式=﹙2﹣x﹚/[x﹙x-1﹚]·[﹙x+1﹚²]/[﹣x﹙3﹣x﹚]·[﹙3﹢x﹚﹙3-x﹚]/[2﹙2-x﹚]
=﹣﹙x+1﹚/2x²
当x=﹣2时
﹣﹙x+1﹚/2x²
= ﹣﹙﹣2+1﹚/2×﹙﹣2﹚²
=﹣﹙1﹣2﹚/﹙2×4﹚
=1/8
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