x²-1分之3x+4-x-1分之2括号除以x²-2x+1分之x+2
=[(3x+4)/(x²-1)-2/(x-1)]÷[(x+2)/(x²-2x+1)]
=[(3x+4)/[(x-1)(x+1)]-2/(x-1)]×[(x-1)²/(x+2)]
=[(3x+4)/(x+1)-2]×[(x-1)/(x+2)]
=[3x+4-2(x+1)]×(x-1)/[(x+2)(x+1)]
=(x+2)×(x-1)/[(x+2)(x+1)]
=(x-1)/(x+1)
内容全部来源于网络收集，如有侵权，请联系网站删除：QQ：24596024