x²-1分之3x+4-x-1分之2括号除以x²-2x+1分之x+2=[(3x+4)/(x²-1)- 2/(x-1)]*(x²-2x+1)/(x+2)=[(3x+4)/(x²-1)- 2/(x-1)]*(x-1)²/(x+2)=[(3x+4)/(x+1)- 2]*(x-1)/(x+2)=(3x+4-2x-2)/(x+1)*(x-1)/(x+2)=(x+2)/(x+1)*(x-1)/(x+2)=(x-1)/(x+1)