x²-1分之3x+4-x-1分之2括号除以x²-2x+1分之x+2

2024-12-16 13:04:04
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回答1:

x²-1分之3x+4-x-1分之2括号除以x²-2x+1分之x+2
=[(3x+4)/(x²-1)- 2/(x-1)]*(x²-2x+1)/(x+2)
=[(3x+4)/(x²-1)- 2/(x-1)]*(x-1)²/(x+2)
=[(3x+4)/(x+1)- 2]*(x-1)/(x+2)
=(3x+4-2x-2)/(x+1)*(x-1)/(x+2)
=(x+2)/(x+1)*(x-1)/(x+2)
=(x-1)/(x+1)