1/(x-2)+1/(x-6)=1/(x-7)+1/(x-1)1/(x-2)-1/(x-1)=1/(x-7)-1/(x-6)(x-1-x+2)/(x-2)(x-1)=(x-6-x+7)/(x-7)(x-6)1/(x-2)(x-1)=1/(x-7)(x-6)(x-7)(x-6)=(x-1)(x-2)x²-13x+42=x²-3x+2-13x+3x=2-42-10x=-40x=4经检验x=4是原方程的解
