先化简再求值(3x+4⼀x눀-1-2⼀x-1)*x-2⼀x눀-2x+1,其中x是不等式组{x+4>0,2x+5<1的整数解

2024-12-14 21:29:23
推荐回答(3个)
回答1:

http://www.jyeoo.com/math/ques/detail/98805efa-bcc1-4b3c-9eb1-716ca077f534参考资料:

回答2:

x是不等式组{x+4>0,2x+5<1的整数解
x+4>0
x>-4
2x+5<1
x<-2
则x=-3
(3x+4/x²-1-2/x-1)*x-2/x²-2x+1,
=[3x+4-2(x+1)]/(x²-1) *(x-2)/(x-1)²
=(x+2)/(x²-1) *(x-2)/(x-1)²
=(x²-4)/(x²-1)(x-1)²
=((-3)²-4)/((-3)²-1)(-3-1)²
=(9-4)/(9-1)(-4)²
=5/(8*16)
=5/128

回答3: