已知tan(派-a)=-2,求3sina+2cosa尀5sina-cosa 求sina∠cosa

2025-02-02 18:52:20
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回答1:

tan(派-a)=-2 => tana=2

(3sina+2cosa)/(5sina-cosa)

=(3tana+2)/(5tana-1)
=8/9

sina•cosa
=(1/2)sin(2a)

=tana/(tan^2a+1)

=2/5