(x+2⼀x^2-2x)-(x-1⼀x^2-4x+4)⼀(4-x⼀x) 要过程!!!!!

2024-12-20 15:58:31
推荐回答(1个)
回答1:

(x+2/x^2-2x)-(x-1/x^2-4x+4)/(4-x/x)
=((x+2)/[x(x-2)]-((x-1)/(x-2)^2)/[(4-x)/x]
=[(x^2-4)-x(x-1)]/[x(x-2)^2]/[(4-x)/x]
=(x-4)/{x(x-2)^2]* x/(4-x)
=-1/(x-2)^2