∫ 1⼀(x^2-1) dx怎么求 要详细步骤

2025-01-02 04:34:41
推荐回答(1个)
回答1:

∫ 1/(x^2-1) dx
=1/2∫【1/(x-1)-1/(x+1)】dx
=1/2[ln\x-1\-ln\x+1\]+c
=1/2ln l(x-1)/(x+1)l+c