(log4上面3+log8上面3)乘以(log3上面2+log9上面2)—log上面4次根号32=?

2024-12-16 02:59:39
推荐回答(1个)
回答1:

(log4(3)+log8(3))(log3(2)+log9(2))—log4(32)^1/4
=(1/2log2(3)+1/3log2(3))(log3(2)+1/2log3(2))-1/4*2log2(32)
=5/6log2(3)*3/2log3(2)-1/2log2(32)
=5/6*3/2*6log2(3)*2log3(2)-1/2[log2(8)+log2(4)]
=5/4-1/2[log2(2)^3+log2(2)^2]
=5/4-1/2(3+2)
= -5/4