解方程:(1)2x눀+3x-1=0 (2)x눀+3=2√3x (3)(2x+1)눀=(x-3)눀

2024-12-28 15:31:15
推荐回答(1个)
回答1:

(1)2x²+3x-1=0
x=[-3-√(9+8)]/2*2=(-3-√17)/4或(-3+√17)/4

(2)x²+3=2√3x
(x-√3)^2=0
x=√3

(3)(2x+1)²=(x-3)²
4x^2+4x+1=x^2-6x+9
3x^2+10x-8=0
(3x-2)(x+4)=0
x=2/3或x=-4