一道java数组习题求助!!!!

2025-02-11 17:57:53
推荐回答(3个)
回答1:

先算出长度,再填。

import java.util.Arrays;
public class Test{
public static void main(String[] args){
int a[][]={
{17,23,1,5},
{8,9},
{34,35,56}
};
int b[]=new int[a.length+a[0].length+a[1].length+a[2].length];
int offset=0;
for(int e[]:a){
b[offset++]=e.length;
System.arraycopy(e, 0, b, offset, e.length);
offset+=e.length;
}
System.out.println(Arrays.toString(b));
}
}
=====
[4, 17, 23, 1, 5, 2, 8, 9, 3, 34, 35, 56]

回答2:

public class Demo {
public static void main(String[] args) {
int srcArray[][]={{17,23,1,5},{8,9},{34,35,56},{1}};// 源数组
int aLength = srcArray.length;// 源数组的第一维度,需要通过第一维来计算第二维长度
int bLength = 0;// 目标数组的长度
for (int i = 0; i < aLength; i++) {
bLength = bLength + srcArray[i].length + 1;// 目标数组的长度=源数组的每一维长度 + 1
}
int targetArray[] = new int[bLength];// 根据长度来初始化目标数组
int offset = 0;
for (int i = 0; i < aLength; i++) {
int aaLength = srcArray[i].length;
targetArray[offset++] = aaLength;// 每一次都首先将源数组长度优先放入目标数组中
for (int j = 0; j < aaLength; j++){
targetArray[offset++] = srcArray[i][j];// 依次找出源数组的每个元素,放入目标数组中
}
}
for (int res : targetArray) {
System.out.println (res);// 打印结果
}
}
}

回答3:

public class ArrayTest{
public static void main(String args[]){
int [][]rs = {{17,23,1,5},{8,9},{34,35,56}};
ArrayTest test = new ArrayTest();
int []res = test.conv(rs);
for(int i = 0; i < res.length; i++){
System.out.print("" + res[i] + " , ");
}
}

public int [] conv(int [][] arr){

int row = arr.length;
int cols = 0;
for(int i = 0; i < row ; i++){ cols++;
for(int j = 0 ; j < arr[i].length; j++){
cols++;
}
}
int [] res = new int[cols];
int s = 0;
for(int i = 0; i < row ; i++){
res[s] = arr[i].length;
s++;
for(int j = 0 ; j < arr[i].length && s < cols; j++){

res[s] = arr[i][j];
s++;
}

} return res;
}
}

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