变压器中,为什么减少原边的匝数会使励磁电流升高?原本工作在额定状态

2024-12-03 13:17:52
推荐回答(5个)
回答1:

这样跟你解释吧,变压器是通过电磁转换还改变电压的,原边减少绕组匝数,就降低了输入电压。电压降低,所以电流就会增大。电压x电流=功率!你注意看变压器的高压端的线径比较细,低压段的线径比较粗就是这个原因!!!

回答2:

变压器的原边空载电流反比于原边绕阻的阻抗。而原边的阻抗与绕组的匝数的平方成正比。所以减小匝数,绕组的阻抗降低,当然电流就会增大。
如果不理解,你可以把原边想象成一个电感。

回答3:

原边匝数减少,使原边的励磁电抗降低(励磁电抗与匝数的平方成正比),故励磁电流增大。

回答4:

当变压器原边的输入电压不变时,减少原边匝数就是着减小了原边的电感量,电感量下降感抗也就下降,相当于原边的电阻减小,电流肯定要上升。

回答5:

原副边电流比等于原副边匝数反比(I1/I2=N2/N1);
输入额定电压,在副边感应电压会增大,副边负载在不变条件下,副边电流会增大,通过比例可见,原边电流会变大。

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