已知函数f（x）=根3sinxcosx-cos^2x+1/2
=根3/2sin2x-1/2cos2x
=sin(2x-π/6)
f（x）=根号3sinxcosx+cos^2x-1/2
=(根号3)*sin2x/2+(1+cos2x)/2-1/2
=sin(2x+π/6)
∴最小正周期=2π/2=π
f(x)=(√3)sinxcosx－cos²x＋(1/2)
=(√3/2)sin2x－(1/2)[cos2x＋1]＋(1/2)
=(√3/2)sin2x－(1/2)cos2x
=sin(2x－π/6)
sin(2x-π/6)
原式=根3/2 Sin2x-1/2 Cos2x =(S|n2×-兀/6)
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